[php] 디비데이터를 JSON으로 출력하기 > 팁앤테크

• 목록

• 페이스북 공유
• 트위터 공유
• 

<?php
include_once('./_common.php');

$result = sql_query("select * from vn_content");
$rows = array();
while ($row = mysql_fetch_assoc($result))
    {
        $JSONres = array
        (  
            "bg"        => urlencode($row['bg']),
            "bg_size"   => urlencode($row['bg_size']),
            "cter"   => urlencode($row['cter']),
            "cter_size"   => urlencode($row['cter_size']),
            "snd"   => urlencode($row['snd']),
            "snd_size"   => urlencode($row['snd_size']),
            "vib"   => urlencode($row['vib']),
            "txt"   => urlencode($row['txt'])
        );
        array_push($rows, $JSONres);
    }
    
echo (strip_tags(urldecode(json_encode($rows))));
?>

추천0